device: limit allowedip fuzzer a to 4 times through
Trying this for every peer winds up being very slow and precludes it from acceptable runtime in the CI, so reduce this to 4. Signed-off-by: Jason A. Donenfeld <Jason@zx2c4.com>
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@ -14,6 +14,7 @@ import (
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const (
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const (
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NumberOfPeers = 100
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NumberOfPeers = 100
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NumberOfPeerRemovals = 4
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NumberOfAddresses = 250
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NumberOfAddresses = 250
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NumberOfTests = 10000
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NumberOfTests = 10000
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)
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)
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@ -103,7 +104,8 @@ func TestTrieRandom(t *testing.T) {
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slow6 = slow6.Insert(addr6[:], cidr, peers[index])
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slow6 = slow6.Insert(addr6[:], cidr, peers[index])
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}
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}
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for p := 0; ; p++ {
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var p int
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for p = 0; ; p++ {
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for n := 0; n < NumberOfTests; n++ {
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for n := 0; n < NumberOfTests; n++ {
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var addr4 [4]byte
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var addr4 [4]byte
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rand.Read(addr4[:])
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rand.Read(addr4[:])
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@ -121,13 +123,16 @@ func TestTrieRandom(t *testing.T) {
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t.Errorf("Trie did not match naive implementation, for %v: want %p, got %p", net.IP(addr6[:]), peer1, peer2)
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t.Errorf("Trie did not match naive implementation, for %v: want %p, got %p", net.IP(addr6[:]), peer1, peer2)
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}
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}
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}
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}
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if p >= len(peers) {
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if p >= len(peers) || p >= NumberOfPeerRemovals {
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break
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break
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}
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}
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allowedIPs.RemoveByPeer(peers[p])
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allowedIPs.RemoveByPeer(peers[p])
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slow4 = slow4.RemoveByPeer(peers[p])
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slow4 = slow4.RemoveByPeer(peers[p])
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slow6 = slow6.RemoveByPeer(peers[p])
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slow6 = slow6.RemoveByPeer(peers[p])
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}
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}
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for ; p < len(peers); p++ {
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allowedIPs.RemoveByPeer(peers[p])
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}
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if allowedIPs.IPv4 != nil || allowedIPs.IPv6 != nil {
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if allowedIPs.IPv4 != nil || allowedIPs.IPv6 != nil {
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t.Error("Failed to remove all nodes from trie by peer")
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t.Error("Failed to remove all nodes from trie by peer")
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